If p(a)=1/2 p(b)=1/3 p(ab)= 1/6, Then find p(a’∩ b’)
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Its very easy , if one uses Addition as well as Multiplication theorems of probability . We know that if A, B are two independent events then by Multiplication theorem of probability P(AB ) = P(A) P(B) . Now by Addition theorem of probability :
P( A U B ) = P(A) + P(B) - P(AB)
= P(A) + P(B) - P(A) P(B) as A, B are independent.
= (1/2) + (1/3) - (1/2)(1/3) = 4/6 = 2/3
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