If P(A)=5/100,P(B)=10/100 and P(AnB)=2/100,then P(AUB)=
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6
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well, given us
P( A ) = 5/100 = 1/20
P( B ) = 10/100 = 1/10
P ( A n B ) = 2/100 = 1/ 50
P ( A U B ) = ?
we know that two formulas are
→ P ( A U B ) = P ( A - B ) + P ( A n B ) + P ( B - A )
→ P ( A U B ) = P ( A ) + P ( B ) - P ( A n B )
which formula we will use ?
definitely we will use 2 nd formula, no doubt.
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P ( A U B ) = P ( A ) + P ( B ) - P ( A n B )
= 1/20 + 1/10 - 1/50
= 5 + 10 - 2 / 100
= 13/100
hence, P ( A U B ) = 13/100
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max23:
its answer is wrong
you forgot to add minus to 1/50
@addision.. try writing answer in less number of steps/lines...but writing enough so that inquirer /reader understands..
chk 4th line from the last..
Answered by
5
Use the rule: (for two sets A and B).
n(A U B) = n(A) + n(B) - n(A ∩ B)
Divide by the number of elements in the Universal set. We get:
P(A U B) = P(A) + P(B) - P(A∩B), for any two sets.
= [5 + 10 - 2]/100 = 13/100
n(A U B) = n(A) + n(B) - n(A ∩ B)
Divide by the number of elements in the Universal set. We get:
P(A U B) = P(A) + P(B) - P(A∩B), for any two sets.
= [5 + 10 - 2]/100 = 13/100
hope that's right.
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