Question

If P (A⋃B) = 0.8 and P (A⋂B) = 0.3 then P(A')+P(B')=?

Answer 1

Answer:

Step-by-step explanation:

P(A')=1-P(A)

P(B')=1-P(B)

And

P(A∪B)=P(A)+P(B)-P(A∩B)

P(A∪B)=1-P(A')+1-P(B')-P(A∩B)

P(A')+P(B')=2-P(A∩B)-P(A∪B) =2-0.3-0.8= 0.9