Math, asked by gnegi9801, 7 months ago

. If P (a, b) lies in II quadrant then which of the following is true about a and b?

(a) a > 0, b > 0 (b) a > 0, b < 0 (c) a < 0, b > 0 (d) a < 0, b < 0​

Answers

Answered by Ritikadatta
25

The answer is option C

In second quadrant x is negative and y is positive

so, let us assume a= -3 (x axis )and b= 2 (y axis)

  • In option (a) it is given that -3 is greater than 0 and 2 is also grater than 0, which is wrong because we know that -3 is smaller than 0.
  • In option (b) it is given that -3 is greater than 0 and 2 is smaller than 0 . it's wrong because -3 is smaller than 0 and 2 is greater than 0.
  • In option (d) it's given that-3 a s smaller than 0 and 2 is smaller than 0 . it's wrong because 2 is greater than 0.

option ( c) is the right one because in this option it's given that -3 is smaller than 0 and 2 is greater than 0.

hope this could help you.

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Answered by pulakmath007
13

SOLUTION

TO CHOOSE THE CORRECT OPTION

If P (a, b) lies in II quadrant then which of the following is true about a and b

(a) a > 0 , b > 0

(b) a > 0 , b < 0

(c) a < 0 , b > 0

(d) a < 0 , b < 0

EVALUATION

We know that in two dimensional geometry the Cartesian plane is divided by coordinate axis in 4 quadrant

1. Quadrant I : Both the x - coordinates and y - coordinates are positive

2. Quadrant II : The x - coordinate is negative and the y - coordinate is positive

3. Quadrant III : Both the x - coordinates and y - coordinates are negative

4. Quadrant IV : The x - coordinate is positive and the y - coordinate is negative

Here the given point is P(a, b)

x - coordinates = a

y - coordinates = b

Since P (a, b) lies in II quadrant

So x - coordinate is negative and the y - coordinate is positive

Thus we get a < 0 , b > 0

FINAL ANSWER

Hence the correct option is (c) a < 0 , b > 0

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