If P(A/B) = P(B\A) Then Prove that P(A) - = P(B)
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This statement will only be true in the event that P(A) = P(B) since by Bayes’ Theorem we have that
P(A|B)=P(A)P(B|A)P(B)=P(B|A)
if and only if P(A) = P(B).
However, like Justin Rising points out, we have to also consider the event that A and B are mutually exclusive, that is the event that A∩B=∅. Assuming this is the case, and that the events A and B both have probability measure larger than zero, we then have
P(A|B)=P(A∩B)P(B)=0P(B)=P(B∩A)P(A)=P(B|A).
So summing it up, we have that if
P(A)=P(B) or P(A∩B)=0 ⇒ P(A|B)=P(B|A).
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