if p=a-b,q=b-c and r=c-a find the value of the xP+xQ+xR
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Answer:
Step-by-step explanation:
(xp/xq)p+q*
(xq/xr)q+r*
(xr/xp)r+p
=(xp-q)p+q*
(xq-r)q+r*
(xr-p)r+p
=(x)p2-q2*
(x)q2-r2*
(x)r2-p2
=(x)p2-q2+q2-r2+r2-p2
=(x)0
=1
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