Question

if p A is directly proportional to q² and the value of p =4 and q= 2 then find the value of q+1 when the value of p is 9​

Answer 1

wait

pA = constant q²

A = constant q²/p

A = 4/4 =1

now

again

Ap = constant q²

1×9 = constant q².....

..................... ( neglect constant for some tym)

q = +3 or _3

THEREFORE q+1 = 4 or _2

Answer 2

p ∝ $q^{2}$

To find constant :

$4 = k(2)^{2}$

4 = 4k

k = 1

9 = $q^{2}$

q = 3

So q + 1

= 3 + 1

= 4

hope it helps and pls mark Brainliest