IF
P=AF^2 + B/AV^2
find dimension of A and B IF P is momentum, F is force, V is velocity
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Answer:
[A] =[M⁻¹L⁻¹T³]
[B] = [M⁰LT]
Explanation:
Given
P = AF² + B/AV²
therefore [P] = [AF²] = [B/AV²]
[P] = [AF²]
{MLT⁻¹] = [A]{MLT⁻²]²
[A] =[M⁻¹L⁻¹T³]
[P] = [B/AV²]
[MLT⁻¹] = [B]/[M⁻¹L⁻¹T³][M⁰LT⁻¹]
[MLT⁻¹] = [B]/[M⁻¹L⁰T²]
[B] = [M⁰LT]
Thank You !!
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