Question

If p & q are 2 real numbers such that
p^2 + q^2 - 4p + 6q + 13 = 0 then p+q=
(A) 1
(B) -1
(C) 0
(D) 2

Answer 1

Step-by-step explanation:

given p^2 + q^2 - 4p + 6q + 13 = 0

we write it as p^2 -4p+4+ q^2 + 6q + 9=0

now (p-2)²+(q+3)²=0

so p=2 and q=-3

and p+q=2-3=-1