Question

If p & q are roots of equati 2x^2-5x+7=0 then the value of (p^2+q^2)

Answer 1

Hii !!



P ( x ) = 2X² - 5x + 7


Here,

a = Coefficient of X² = 2

b = Coefficient of X = -5

And,

C = Constant term = 7.





therefore,

Sum of roots = -b/a


( P + Q ) = -(-5) / 2


( P + Q ) = 5/2 -------(1)


And,


Product of roots = c/a


( P × Q ) = 7/2 -------(2)




P and Q are the roots of the given quadratic polynomial.





Therefore,

( P² + Q² ) = ( P + Q )² - 2PQ



( P² + Q² ) = ( 5/2)² - 2 × 7/2


( P² + Q² ) = 25/4 - 7



( P² + Q²) = ( 25 - 28 ) /4



( P² + Q²) = -3/4

Answer 2

Hi Mate!!!

P² + q² = ( p+q )² - 2(pq)

p+q = 5/2. and pq = 7/2

p² + q² = ( 5/2)² - 2 ( 7/2)

p² + q² = -3/4

Have a nice time.