Question

if p,and p2 are two odd prime no. such that p1 >p2 then p1^2-p2^2 is​

Answer 1

Answer:

an even number

Step-by-step explanation:

Let the two odd prime numbers p1 and p2 be 7 and 5 respectively.

Then, p

1

2

=7

2

=49

and, p

2

2

=5

2

=25

So, p

1

2

−p

1

2

=49−25=24 which is an even number.

Take another examples with p

1

and p

2

be 17 and 13.

Then, p

1

2

=17

2

=289

and, p

2

2

=13

2

=169

So, p

1

2

−p

1

2

=289−169=120 which is an even number.

In general the square of odd prime number is odd.

Hence, the difference of square of two prime numbers is even.