if p and q are any two points lying on side DC and AD respectively of a parallelogram ABCD ,then :
A. ar(APB) > ar(BQC)
B. ar(APB) < ar(BQC)
C. ar(APB) = ar(BQC)
D. None of above
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Answer:
Since △APB and parallelogram ABCD are on the same base AB and between the same parallels.
Therefore,
ar(△APB)=
2
1
ar(∥
gm
ABCD) .......(1)
Similarly,
ar(△BQC)=
2
1
ar(∥
gm
ABCD) ......(2)
From 1 and 2, we get,
ar(△APB)=ar(△BQC
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