If P and q are any two statements, prove that ( ∨ ) ≡ ( ∧ )
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∼p∧∼q
∼(p∨(∼p∧q))
=∼p∧∼(∼p∧q)
=∼p∧(p∨∼q)
=(∼p∧p)∨(∼p∧∼q)
=F∨(∼p∧∼q)
=(∼p∧∼q).
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