Question

if p and q are are the roots of x square + 2 X + 1 is equal to zero then the value of P Cube + Q cube becomes​

Answer 1

Answer:

x^2+2x+1=0

x^2+X+X+1=0

X(X+1)+X(X+1)=0

(X+1)(X+1)=0

p=-1,q=-1.

p^3+q^3=(-1)^3+(-1)^3

=-1-1=-2.

Answer 2

Step-by-step explanation:

$(x + 1)^{2} = {x}^{2} + 2x + 1$=0 (given)

So, roots of the given equation is -1

then p = -1 & q = -1

p^3 + q^3 = (-1)^3+(-1)^3 = -2