if p and q are are the roots of x square + 2 X + 1 is equal to zero then the value of P Cube + Q cube becomes
Answers
Answered by
6
Answer:
x^2+2x+1=0
x^2+X+X+1=0
X(X+1)+X(X+1)=0
(X+1)(X+1)=0
p=-1,q=-1.
p^3+q^3=(-1)^3+(-1)^3
=-1-1=-2.
Answered by
1
Step-by-step explanation:
=0 (given)
So, roots of the given equation is -1
then p = -1 & q = -1
p^3 + q^3 = (-1)^3+(-1)^3 = -2
Similar questions