Question

If p and q are non-zero constants and the equation x?+px+q=0 has roots a and B, then the equation
qx?+px+1=0 has roots
(1) a and 1/B (2) 1/ B and a (3) 1/ a and 1/B
(4) None of these​

Answer 1

Answer:

sum of roots =-p=a+B

product of roots=q=aB

for second equation

sum of roots =-p/q=a+B/aB=1/B+1/a

product of roots=1/q=1/aB

root of second equation are 1/a,1/B