Question

If p and q are positive integers each greater than 1,and 17(p+1)=29(q+1),what is the least possible value of p+q?

Answer 1

Answer:

l.c.m of 17 and 29=

17×29=493

hence,17(p+1)=29(q+1)=493

or,p+1=29 and q+1=17

or,p=28 and q=16

or,p+q=44,where p and q are at their respective minimum values.