Question

if p and q are positive integers, what is the remainder when 92p

Answer 1

your question is incomplete.

get it corrected.

Answer 2

1 is the Answer!

Step-by-step explanation:

Here is the Solution =>

let n = 9^2p × 5^(p+q) + 11^q × 6^pq

Rule used => The remainder whenever an integer is divided by 10 is same as its units digit.

As a side note => In order to get the remainder with 2,5 or 10 --> We just need the units digit.

So we actually need the units digit of n

Applying the concept of cyclicity

Units digit of n=> 1*5+1*6=>5+6 =>1

Hence the units digit will be one and so will the remainder when n is divided by 10.

So, Answer is 1.