Question

If p and q are roots of quadratic equation X square - 6 X + 5 = 0 then P Cube + Q cube is

Answer 1

Answer:

126

Step-by-step explanation:

using splitting the method formula for the equation

(product = 5 and sum = -6)

splitting the equation x*2 - 6x + 5 = 0

we get

x*2 - x - 5x + 5 = 0

x(x-1) - 5(x-1) = 0

x-1 = 0 OR x-5 = 0

x=1 OR x=5

according to the question it is given that p and q are roots of the equation.

Therefore we can take p = 1 and q = 5

substituting these values in p*3 + q*3

we get

1*3 + 5*3 = 1 + 125

= 126