Question

If p and q are roots of the equation x² - px + q = 0, then
(a) p = 1, q = -2
(b) b = 0, q = 1
(c) p = -2, q = 0
(d) p = -2, q = 1​

Answer 1

Step-by-step explanation:

Given that

p and q be the roots of the equation x^ 2 - px + q = 0

To find

the value of p and q.

Here, a = 1, b = - p and c = q

p and q be the roots of the given equation

Therefore, sum of the roots

$\bf{p + q = \frac{ - b}{a} } \\ \bf{ = \frac{- p}{1}} \\ \bf = - p \\ \bf \: q = - p - p \\ \bf = - 2p...1$

Now,

Product of the roots

we know that

$\bf \: p \times q = \frac{q}{1} \\ \bf \: p = \frac{q}{q} \\ \bf \: = 1$

Putting the value of p = 1 in equation (1)

$\bf \: q = - 2 \times 1 \\ \bf \: = - 2$

$\boxed{ \red{\pmb{Therefore, \: the \: value \: of \: p=1; \: q=-2 .}}}$

Answer 2

Answer:

p = -2 and q = 0

Step-by-step explanation:

step by step explanation is given in the picture above