Question

If p and q are roots ofx^2+2x+1=0 then the value of p^3+q^3 becomes

Answer 1

$\: \: \: \: \: \: \: {x}^{2} + 2x + 1 = 0 \\ = > {x}^{2} + x + x + 1 = 0 \\ = > x(x + 1) + 1(x + 1) = 0 \\ = > (x + 1)(x + 1) = 0 \\ = > x = ( - 1).$


Therefore,
p = q = (-1).
$\: \: \: \: \: {p}^{3} + {q}^{3} \\ = {( - 1)}^{3} + {( - 1)}^{3} \\ = - 1 - 1 \\ = ( - 2).$




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