If p and q are sum of n succesive integers (where first term is a) and their squares then nq-psquare Will be -
1)independent of a 2)independent of n 3)depends on a 4)none of these
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p=n/2(2a + (n-1)1 )
the common difference is 1 since the numbers are successive integers.
q is n(n+1)(2n+1)/6 - a(a+1)(2a+1)/6
solve it from here.
if you still have doubts, ask
the common difference is 1 since the numbers are successive integers.
q is n(n+1)(2n+1)/6 - a(a+1)(2a+1)/6
solve it from here.
if you still have doubts, ask
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kaushikravikant:
Its answer is independent of a
R u solving or not
Hey, r u solving,
i am, i kno d ans depends on n, vl tel wen m done
Is it depends upon a or not
i can't solve that.. i tried, m sry, its cumin a polynomial of d power 3 multiplied wid n
Kk
For getting, my question,'s answer
I have to delete ur answer
han
Answered by
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Answer:
independent of A
Step-by-step explanation:
so, OUR answer is a
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