if p and q are the coefficients of x power n in the expansion of oneplus x whole power 2n and one plus x whole power 2 and -1 respectively then p by q is equals to
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Given : p and q are the coefficients of xⁿ in the expansion of (1 + x)²ⁿ and (1 + x)²ⁿ⁻¹ respectively
To Find : p/q
Solution:
coefficients of xⁿ in the expansion of (1 + x)²ⁿ
= ²ⁿCₙ
=> p = ²ⁿCₙ
=> p = (2n)!/n!.(2n-n)!
=> p = (2n)!/n!.n!
coefficients of xⁿ in the expansion of (1 + x)²ⁿ⁻¹
= ²ⁿ⁻¹Cₙ
=> q = ²ⁿ⁻¹Cₙ
=> q = (2n-1)!/n!.(2n-1-n)!
=> q = (2n)!/n!.(n-1)!
p = (2n)!/n!.n!
=> p = 2n.(2n-1)!/n!. n(n-1)!
=> p = 2 . (2n)!/n!.(n-1)!
=> p = 2.q
=> p/q = 2
Hence p/q = 2
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