Question

If p and q are the roots of ax2-bx+C=0,a≠0, then find the value of p+q.​

Answer 1

Answer:

b/a

Step-by-step explanation:

Sum of roots = -(coefficient of x)/coefficient of x²

= -(-b)/a = b/a

Answer 2

Step-by-step explanation:

We have here a quadratic equation. When we find the roots of an equation such as this, we use the quadratic formula:

x = (-b ± √(b2 - 4ac)) / 2a

where a, b, and c are coefficients.

In this equation

a = a

b = -b

c = c

The plus/minus sign indicates that we will have two solutions. Suppose that root p was found using the plus and root q was found using the minus. We will have these roots.

p = (b + √(b2 - 4ac)) / 2a and q = (b - √(b2 - 4ac)) / 2a

Since we want to find the value of p + q, we simply add the formula.

p + q = ((b + √(b2 - 4ac)) + (b - √(b2 - 4ac))) / 2a

The square-root terms cancel each other out.

p + q = 2b / 2a

p + q = b / a

Hope this helps!