if p and q are the roots of quadratic equation x square-px+q=0,then
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2
Answer:-
Sum of roots = p
=> p + q = p
=> q = 0
Product of roots = q
=> pq = q
=> pq - q = 0
=> q (p - 1) = 0
=> q = 0, p = 1
The values of p and q hence found are p = 1, and q = 0. This makes the original equation x^2 - x = 0.
Answered by
1
Answer:
Given S = p + q = – p and product pq = q
This implies, q(p – 1) = 0 i.e. q = 0, p = 1
Now If q = 0 then p = 0, this implies p = q
If p = 1, then p + q = – p
q = – 2p
q = – 2(1)
q = – 2
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