If p and q are the roots of the equation 2a2 – 4a + 1 = 0. Find the value of
(i) (p + q)2 + 4pq
(ii) p3 + q3
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if ax²+bx+c=0 is a equation then sum of roots = -b/a
product = c/a
(p + q)2 + 4pq = (-(-4)/2)²+4(1/2)
= 4+2=6
p3 + q3 = (p+q)³-3pq(p+q)
= -(-4)/2)³-3(1/2)(-(-4)/2)
= 8-3 = 5
Step-by-step explanation:
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