Question

if p and q are the roots of the equation bx2 +2x+1=0 find the value of 1/pq-1/pq​

Answer 1

Answer:

Given:

(1 + √2)x2 – (√5 + √10)x + (1 + √2)

Roots of equation: p and q

Concept Used:

If a quadratic equation (ax2 + bx + c = 0)

Then, p + q = - b/a and pq = c/a

Calculation:

(1 + √2)x2 – (√5 + √10)x + (1 + √2)

p + q = -(- √5 - √10)/(1 + √2) = √5 [ 1 + √2]/(1 + √2) = √5

pq = (1 + √2)/(1 + √2) = 1

So, (p + q) = √5 and pq = 1

Now, (p – q) = √[(p + q)2 – 4pq]

⇒ √[(√5)2 – 4(1)]

⇒ √(5 – 4)

⇒ 1

Answer 2

Plz don't give s t u p id answer.