if p and q are the roots of the equation X square - 2 x minus 1 is equals to zero find the quadratic equation in X whose roots are p + q whole square and p minus q whole square
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Solution :-
Given, p and q be the roots of the equation
x
2
−2x+A=0. So,
p+q=22.....(1)
pq=A...(2)
And, r and s be the roots of the equation
x
2
−18+B=0. So,
r+s=18...(3)
rs=B...(4)
Now, p,q,r and s are in A.P
so let, p=a,q=a+d,r=a+2d,s=a+3d
Now, put these values in equation (1) and (3), we have
a+a+d=2⇒2a+d=2...(5)
And,
a+2a+a+3d=18⇒2a+5d=18...(6)
solving equation (5) and (6),
a=−1, d=4
so p=−1,q=−1+4=3,r=−1+8,s=−1+12=11
Thus,
A=pq=−1×3=−3
B=rs=7×11=77
Then A+B=−3+77=74
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