if p and q are the roots of the equation x square- px +q =0 then p and q
p= 1 , q= 2
p=-2, q=0
p=0 ,q=1
p=-2 ,q=1
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Answer:
Given equation
x
2
+px+q
Also, given p,q are the roots of the equation.
p+q=−p
2p=−q .....(1)
And pq=q
q(p−1)=0
⇒q=0 or p=1
So, by (1), q=0⇒p=0
Hence, the values of p are 0,1.
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