If p and q are the roots of the equation x2-7x+10=0
umaleanurag111:
what is exactly to be find out
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X^2-7x+10 =0
Comparing the eq witj ax^2-bx+c=0
Then p+q=-b/a and pq=c/a
Then p+q=7 and pq=10
Solving both equations, we found p=5 and q=2.
Comparing the eq witj ax^2-bx+c=0
Then p+q=-b/a and pq=c/a
Then p+q=7 and pq=10
Solving both equations, we found p=5 and q=2.
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