If p and q are the roots of the equation x2-px+q=0, then
a) p=1, q=-2 b) p=0, q=1 c) p=-2, q=0 d) p=-2, q=1
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Given equation
x
2
+px+q
Also, given p,q are the roots of the equation.
p+q=−p
2p=−q .....(1)
And pq=q
q(p−1)=0
⇒q=0 or p=1
So, by (1), q=0⇒p=0
Hence, the values of p are 0,1.
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