Question

If p and q are the roots of the equation x² − px + q = 0, then
(a)p = 1, q = −2
(b)b = 0, q = 1
(c)p = −2, q = 0
(d)p = −2, q = 1

Answer 1

SOLUTION :  

Option (a) is correct : p = 1 ,q = - 2

Given : ‘p’ & 'q’ are the roots of the equation x² - px + q = 0

On comparing the given equation with ax² + bx + c = 0  

Here, a = 1 , b = - p  , c = q

Sum of zeroes = - b/a  

p + q  = - b/a

p + q  = - p/1

p + q  = - p

q = - p - p

q = - 2p ………..(1)

Product of zeroes = c/a  

p × q = c/a

pq = q/1

p = q/q

p = 1

On putting the value of p = 1 in eq 1

q = - 2p

q = - 2(1)

q = - 2

Hence, the value of p is 1 & q = - 2.

HOPE THIS ANSWER WILL HELP YOU...

Answer 2

Answer:

p&q are roots,

p²-p(P)+q=0

⇒q=0

so only option is c