Question

If p and q are the roots of the equation x² − px + q = 0, then
(a)p = 1, q = −2
(b)b = 0, q = 1
(c)p = −2, q = 0
(d)p = −2, q = 1​

Answer 1

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Answer 2

Answer:

OPTION C

Step-by-step explanation:

p  and q are the roots of the equation :

x² - p x + q = 0

Sum of roots = - ( co-efficient of the 2 nd term ) / ( co-efficient of 1 st term )

Co-efficient of the first term = 1

Co-efficient of the 2 nd term = - p

Hence p + q = - ( - p )/ 1

⇒ p + q = p

⇒ q = 0

Hence the value of q = 0 .

The answer is will be OPTION C obviously  .

No other option shows that q = 0 .

But I should not be lazy , so I am finding the value of p also :)

Product of roots should be 0 .

Hence q/1 = 0

= q = 0

The equation is shortened to :

x² - p x = 0

p is a solution . Hence x = p .

⇒ p² - p ( p ) = 0

⇒ p² = p² .

So with the information given , we cannot find the value of q .