IF P AND Q ARE THE ROOTS OF THE EQUATION XSQUARE+PX+Q=0 FIND P AND Q
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Eq. x^2+px+q=0
p,q are roots of eq.
Then,
product of roots,pq=q(in form of c/a)
=>p=1. ..(i)
And sum of roots,p+q=-p(-b/a)
=>2p=-q
=>q=-2(1)=-2. [from (i)]
So,p=1 and q=-2
Hope it helps.
p,q are roots of eq.
Then,
product of roots,pq=q(in form of c/a)
=>p=1. ..(i)
And sum of roots,p+q=-p(-b/a)
=>2p=-q
=>q=-2(1)=-2. [from (i)]
So,p=1 and q=-2
Hope it helps.
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