if p and q are the roots of x^2+2x+1=0 then the value of p^3+q^3 is
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p³+q³ = (p+q)³-3pq(p+q)
From given equation x²+2x+1=0;
sum of roots p+q = -x coefficient/x² coefficient = -2
Product of roots pq=constant term/x² coefficient = 1
So p³+q³ = (-2)³-3(1)(-2) = -8+6 = 2
connor74:
wrong answer bai
theres a sign mistake its -8 +6 = -2
ya
but in text it is 2
No the roots are -1 and -1 so (-1)^3+(-1)^3=-2
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