Question

If p and q are the roots of x2+2x+1=0 then the values of p3+q3 becomes

Answer 1

Answer:

p^3 + q^3 = 2

p= -1 & q= -1

Step-by-step explanation:

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Answer 2

Concept-

The roots of equation are the values ​​of the variable which satisfies the equation. they're also called the "zeros" of the quadratic. for instance, the roots of the equation x2 - 7x + 10 = 0 are x = 2 and x = 5 because they satisfy the equation.

Given-

p and q are the roots of x² + 2x + 1 = 0

Find-

Find the worth of p³ + q³.

Solution-

p, q are the roots of x² + 2x + 1 = 0

f(p) = p² + 2p + 1 = 0

⇒ (p + 1)² = 0

⇒ p = -1

f(q) = q² + 2q + 1 = 0

⇒ (q + 1)² = 0

⇒ q = -1

p³ + q³

(-1)³ + (-1)³

-1 + ( -1 )

-1 - 1

-2

Therefore, the worth of p³ + q³ = -2.

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