Question

if p and q are the two digits of the number 653pq such that this number is divisible by 80 then p+q is equal to :

Answer 1

80=2*5*8
Since 653pq is divisible by 2 & 5 both .so y=0
Now,653pis divisible by 8.so 13pshould be divisible by 8
This happens when x=6
p+q=6+0=6

Answer 2

Answer: p+q is equal to 6.

Here is a step-by-step explanation:

A number is divisible by 80 if and only if it is divisible by both 10 and 80.

80 is the product of 10 and 8, so a number is divisible by 80 if and only if it is divisible by 10 and 8.

To be divisible by 10, a number must end in 0, so q must be 0.

Rewrite 653p0 as 6530 * p.

6530 is divisible by 8 because 653 is divisible by 8 and adding 0 to the end of a number does not change whether it is divisible by 8 or not.

Therefore, 653p0 will be divisible by 8, if and only if p = 6.

Hence, p + q = 6 + 0 = 6.

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