Question

If p and q are the zero's of the polynomial x2+5x+8 ,then the value of (p+q).​

Answer 1

Answer:-

x²+5x+8

comparing it with ax²+bc+c

we have , a=1 , b=5 and c=8

let the zeroes be alpha and beta

sum of zeroes = (alpha + beta) = -b/a

from above , -5/1 that is -5

product of zeroes = (alpha × beta) = c/a

from above , 8/1 that's is 8

so , 5 and 8 are the two zeroes

now let p = 5 and q = 8

(p+q) = (5+8)

(p + q) = 13

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Answer 2

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Answer is -5