Question

If p and q are the zeroes of polynomial f(x)= 2x^2-6x+3, find the value of p/q +q/p

Answer 1

Answer:

p/q + q/p = (p^2 + q^2)/pq

We know that:

Sum of zeroes = -b/a

Product of zeroes = c/a

(p + q) = -b/a = 6/2 = 3

Squaring on both sides:

=> (p + q)^2 = 3^2

=> p^2 + q^2 + 2pq = 9

pq = c/a = 3/2

=> p^2 + q^2 = 9 - 2(3/2)

=> p^2 + q^2 = 6

p/q + q/p = 6/3/2 = 4

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