Question

If p and q are the zeroes of the polynomial 2 - 3x - x^2, then p + q

Answer 1

Answer:

1

Step-by-step explanation:

$-x^{2} -3x+2=0\\-(x^{2} +3x-2)=0\\x^{2} -2x+x-2=0\\x(x-2)+1(x-2)=0\\(x+1)(x-2)=0\\x=-1,2\\if \\p=-1\\q=2\\p+q=-1+2=1\\if\\p=2\\q=-1\\p+q=2-1=1$

Answer 2

Step-by-step explanation:

both are correct p= -2 or q = 1

p= 1 or q= -2