Question

If p and q are the zeroes of the polynomial
$x^{2} + 7x + 16$
then the value of p/q and q/p is:

(a)
$\frac{49}{10}$
(b)
$\frac{29}{10}$
(c)
$\frac{39}{10}$
(d) 6



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Answer 1

Answer:

Step-by-step explanation:

Given: f(x)=2x^2-7x+3

= 2x^2 - 6x -x +3

= 2x(x-3) -1(x-3)

=(2x-1)(x-3)

Hence, x=3 & x=1/2. 0r p=3 & q=1/2

Therefore, p^2 + q^2 = 3×3 + 1/2×1/2 = 9 + 1/4 = 37/4

Hope I was helpful.. :D