Question

if p and q are the zeroes of the polynomial x2 + 7x +7, then form a quadractic polynomial whose zeroes are 2p and 2q

Answer 1

p+q= -b/a. (Alpha + beta)
= -7

p×q= c/a
= 7

New zeros sum = 2p+2q= 2(p+q) = 2×-7= -14
Product of zeros = 2p×2q= 4pq= 4×7= 28
The polynomial is x2+14x+28.