Question

If p and q are the zeros of the polynomial f(x)= 2x2-7x+3, find the value of p2 +q2

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$\sf \dfrac{37}{4}$

Step-by-step explanation:

Given:

'p' and 'q' are the zeroes of a polynomial.

f(x) = 2x² - 7x + 3

To Find:

Value of p² + q²

Solution.

Step 1: Find the zeroes of the polynomial.

2x² - 7x + 3

-7x can be split as -1x and -6x.

2x² - 1x - 6x + 3

x (2x - 1) -3 (2x - 1)

(x - 3) (2x - 1)

'p' and 'q' are zeroes.

∴ p = 3 and q = 1/2

Step 2: Substitute the values of 'p' and 'q' in p² + q²

p² + q²

$\sf = [3]^{2} + [\frac{1}{2}]^{2}$

$\sf = 9 \ + \dfrac{1}{4}$

$\sf = \dfrac{36 \ + 1}{4}$

$\sf = \dfrac{37}{4}$

$\sf \therefore The \ answer \ is \ \dfrac{37}{4}$