If p and q are the zeros of the polynomial f (x ) = x2 - 7x + k such that p - q = 1 then the value of k is
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Answer:
The answer is 12
Step-by-step explanation:
The given quadratic equation is
X²-7X+k
If p and q be the zeros so
p+q= -b/a=7
pq=k
since,
p-q=1
then we have
(p+q)²=(p-q)²+4pq
→7²=1²+4k
→k= 12.
hope you have understood..
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