Math, asked by ariko4009, 5 hours ago

If p and q are the zeros of the polynomial f (x ) = x2 - 7x + k such that p - q = 1 then the value of k is

Answers

Answered by labhkumarsharma25
0

Answer:

The answer is 12

Step-by-step explanation:

The given quadratic equation is

X²-7X+k

If p and q be the zeros so

p+q= -b/a=7

pq=k

since,

p-q=1

then we have

(p+q)²=(p-q)²+4pq

→7²=1²+4k

→k= 12.

hope you have understood..

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