Question

If p and q are two unit vectors the angle between is 60 then 1+p.q/1-p.q

Answer 1

As per the question , p and q are 2 unit vectors and angle between them is 60°.

We have to find the value of :

$\dfrac{1 + \vec p. \vec q}{1 - \vec p. \vec q} = \: ?$

First of all, we must remember that magnitude of unit vectors are 1 .

$\therefore \: \vec p. \vec q = | \vec p| \times | \vec q| \times \cos(60 \degree)$

$= > \: \vec p. \vec q = 1 \times 1 \times \dfrac{1}{2}$

$= > \: \vec p. \vec q = \dfrac{1}{2}$

So putting the required value :

$\therefore \: \: \dfrac{1 + \vec p. \vec q}{1 - \vec p. \vec q}$

$= \: \: \dfrac{1 + \frac{1}{2} }{1 - \frac{1}{2} }$

$= \: \: \dfrac{ \frac{3}{2} }{ \frac{1}{2} }$

$= \: \: \dfrac{( \frac{3}{ \cancel2} )}{ (\frac{1}{ \cancel2} )}$

$= 3$

So final answer is 3.

Answer 2

Answer:

3

Explanation:

Dot product or scalar product has been used here..

so therefore see my attachment..

Explanation is given...