if p and q are zeroes of polynomial f(x)=2x^2-7x=3 find the value of p^2 +q^2
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Given polynomial is
Compare with standard quadratic , we get
a=2, b=-7, c=3
We know that sum of roots is given by (-b/a)
so the sum is -(-7)/2 or 7/2
since p and q are the zeros then we can write
p+q=7/2...(i)
product of roots is given by c/a so we get 3/2
which produces equation pq=3/2...(ii)
now we will try to find value of using some rearrangements.
Now plug the values from (i) and (ii)
So the final answer is 37/4.
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