Question

If p and q are zeroes of
$3 {x}^{2} + 2x - 9$
then find value of p - q ..​

Answer 1

Answer:

Answer:

2√2

Step-by-step explanation:

We know, polynomials written in form of x^2 - Sx + P refer S as sum of their roots and P as product of their roots.

 Which, here, in pol. x^2 + 2x - 1

sum of roots = p + q = - 2

product of roots = pq = - 1

 Square on both sides of p + q

⇒ ( p + q )^2 = ( - 2 )^2

⇒ p^2 + q^2 + 2pq = 4

⇒ p^2 + q^2 + 2( - 1 ) = 4

⇒ p^2 + q^2 - 2 = 4

⇒ p^2 + q^2 = 4 + 2 = 6

   Subtract 2pq from both sides

⇒ p^2 + q^2 - 2pq = 6 - 2pq

⇒ ( p - q )^2 = 6 - 2( - 1 )

⇒ ( p - q )^2 = 6 + 2 = 8

⇒ p - q = √8

⇒ p - q = 2√2

Answer 2

Answer:

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