If p and q are zeroes ofthe polynomial t²-4t + 3, show that 1/p +1/q -2pq + 14/3= 0
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Answered by
207
Hi ,
It is given that p , q are two zeroes of the
polynomial p( t ) = t² - 4t + 3
To find p and q we have take p( t ) = 0
t² - 4t + 3 = 0
t² - t - 3t + 3 = 0
t( t - 1 ) - 3( t - 1 ) = 0
( t - 1 )( t - 3 ) = 0
Therefore ,
t - 1 = 0 or t - 3 = 0
t = 1 or t = 3
p = 1 , q = 3
Now ,
1/p + 1/q - 2pq + 14/3
= 1/1 + 1/3 - 2 × 1 × 3 + 14/3
= 1 + 1/3 - 6 + 14/3
= - 5 + ( 1/3 + 14/3 )
= -5 + 15/3
= -5 + 5
= 0
Hence proved.
I hope this helps you.
: )
It is given that p , q are two zeroes of the
polynomial p( t ) = t² - 4t + 3
To find p and q we have take p( t ) = 0
t² - 4t + 3 = 0
t² - t - 3t + 3 = 0
t( t - 1 ) - 3( t - 1 ) = 0
( t - 1 )( t - 3 ) = 0
Therefore ,
t - 1 = 0 or t - 3 = 0
t = 1 or t = 3
p = 1 , q = 3
Now ,
1/p + 1/q - 2pq + 14/3
= 1/1 + 1/3 - 2 × 1 × 3 + 14/3
= 1 + 1/3 - 6 + 14/3
= - 5 + ( 1/3 + 14/3 )
= -5 + 15/3
= -5 + 5
= 0
Hence proved.
I hope this helps you.
: )
saduboi:
Thnx a lot!!!!
Answered by
25
Answer:
p( t ) = t² - 4t + 3
polynomial p( t ) = t² - 4t + 3
To find p and q we have take p( t ) = 0
t² - 4t + 3 = 0
t² - t - 3t + 3 = 0
t( t - 1 ) - 3( t - 1 ) = 0
( t - 1 )( t - 3 ) = 0
Therefore ,
t - 1 = 0 or t - 3 = 0
t = 1 or t = 3
p = 1 , q = 3
Now ,
1/p + 1/q - 2pq + 14/3
= 1/1 + 1/3 - 2 × 1 × 3 + 14/3
= 1 + 1/3 - 6 + 14/3
= - 5 + ( 1/3 + 14/3 )
= -5 + 15/3
= -5 + 5
= 0
Hence proved.
HOPE IT HELP YOU
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