if p and r are the zeroes of the ploynomial f( x) = xsquare- 2x+8 then find psquare+ rsquare
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f(x) = x² - 2x + 8
x²-2x+8=0
x²-4x+2x-8=0
(x+2)(x-4)=0
x+2 = 0
x = -2.
f(p) = p² - 2p + 8
f(r) = r² - 2r + 8
f(p) = f(r)
p² - 2p + 8 = r² - 2r + 8
p² - 2p = r² - 2r
p² - r² = 2p - 2r
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x²-2x+8=0
x²-4x+2x-8=0
(x+2)(x-4)=0
x+2 = 0
x = -2.
f(p) = p² - 2p + 8
f(r) = r² - 2r + 8
f(p) = f(r)
p² - 2p + 8 = r² - 2r + 8
p² - 2p = r² - 2r
p² - r² = 2p - 2r
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Caus I know only this much!!!
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