If p and v are the power and potential of the device, the power consumed with a supply potential v1 is.a)(v1×v1/v×v)pb)(v×v/v1×v1)pc)(v/v1)pd(v1/v)p
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answer : option (a) (v1 × v1/v × v) × p
P is the power and V is the potential of any device. so, resistance of that device would be R = V²/P
now, power consumed with a supply of potential
V1 is , P' = V1²/R
= V1²/(V²)/P
= (V1/V)² × P
hence, power consumed with a supply potential V1 is (V1/V)² × P
hence option (a) is correct choice.
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Answered by
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Answer:
R= V/V1
P1=V1^2/R
so V1^2/V2P is correct
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