Physics, asked by diptimohanty67041, 10 months ago

If p and v are the power and potential of the device, the power consumed with a supply potential v1 is.a)(v1×v1/v×v)pb)(v×v/v1×v1)pc)(v/v1)pd(v1/v)p​

Answers

Answered by abhi178
0

answer : option (a) (v1 × v1/v × v) × p

P is the power and V is the potential of any device. so, resistance of that device would be R = V²/P

now, power consumed with a supply of potential

V1 is , P' = V1²/R

= V1²/(V²)/P

= (V1/V)² × P

hence, power consumed with a supply potential V1 is (V1/V)² × P

hence option (a) is correct choice.

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Answered by kashishvarshney289
0

Answer:

R= V/V1

P1=V1^2/R

so V1^2/V2P is correct

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