If P(E) = 0.05, what is the probability of ‘not E’?
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Answered by
3
SOLUTION P(E) = 0.05
also, P(E) + P(not E) = 1
⇒ P(not E) = 1 - P(E)
⇒ P(not E) = 1 - 0.05
⇒ P(not E) = 0.95
also, P(E) + P(not E) = 1
⇒ P(not E) = 1 - P(E)
⇒ P(not E) = 1 - 0.05
⇒ P(not E) = 0.95
Answered by
3
we know that p(e) + p(not e) = 1
therefore p(not e) = 1 - p(e)
here , p(e) = 0.05
= 0.95
the probability of (not e) = 0.95
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